2(c-3)+4=10

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Solution for 2(c-3)+4=10 equation:



2(c-3)+4=10
We move all terms to the left:
2(c-3)+4-(10)=0
We add all the numbers together, and all the variables
2(c-3)-6=0
We multiply parentheses
2c-6-6=0
We add all the numbers together, and all the variables
2c-12=0
We move all terms containing c to the left, all other terms to the right
2c=12
c=12/2
c=6

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