2(c-3)+5=3(c-1)

Solution for 2(c-3)+5=3(c-1) equation:

Simplifying
2(c + -3) + 5 = 3(c + -1)

Reorder the terms:
2(-3 + c) + 5 = 3(c + -1)
(-3 * 2 + c * 2) + 5 = 3(c + -1)
(-6 + 2c) + 5 = 3(c + -1)

Reorder the terms:
-6 + 5 + 2c = 3(c + -1)

Combine like terms: -6 + 5 = -1
-1 + 2c = 3(c + -1)

Reorder the terms:
-1 + 2c = 3(-1 + c)
-1 + 2c = (-1 * 3 + c * 3)
-1 + 2c = (-3 + 3c)

Solving
-1 + 2c = -3 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
-1 + 2c + -3c = -3 + 3c + -3c

Combine like terms: 2c + -3c = -1c
-1 + -1c = -3 + 3c + -3c

Combine like terms: 3c + -3c = 0
-1 + -1c = -3 + 0
-1 + -1c = -3

Add '1' to each side of the equation.
-1 + 1 + -1c = -3 + 1

Combine like terms: -1 + 1 = 0
0 + -1c = -3 + 1
-1c = -3 + 1

Combine like terms: -3 + 1 = -2
-1c = -2

Divide each side by '-1'.
c = 2

Simplifying
c = 2