2(c-3)-7=12-5(c-2)

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Solution for 2(c-3)-7=12-5(c-2) equation: 



2(c-3)-7=12-5(c-2)

We move all terms to the left:

2(c-3)-7-(12-5(c-2))=0

We multiply parentheses

2c-(12-5(c-2))-6-7=0



We calculate terms in parentheses: -(12-5(c-2)), so:

12-5(c-2)

determiningTheFunctionDomain
-5(c-2)+12

We multiply parentheses

-5c+10+12

We add all the numbers together, and all the variables

-5c+22

Back to the equation:

-(-5c+22)



We add all the numbers together, and all the variables

2c-(-5c+22)-13=0

We get rid of parentheses

2c+5c-22-13=0

We add all the numbers together, and all the variables

7c-35=0

We move all terms containing c to the left, all other terms to the right

7c=35

c=35/7

c=5

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