2(c-3)=2(c-3)+2

Solution for 2(c-3)=2(c-3)+2 equation:

Simplifying
2(c + -3) = 2(c + -3) + 2

Reorder the terms:
2(-3 + c) = 2(c + -3) + 2
(-3 * 2 + c * 2) = 2(c + -3) + 2
(-6 + 2c) = 2(c + -3) + 2

Reorder the terms:
-6 + 2c = 2(-3 + c) + 2
-6 + 2c = (-3 * 2 + c * 2) + 2
-6 + 2c = (-6 + 2c) + 2

Reorder the terms:
-6 + 2c = -6 + 2 + 2c

Combine like terms: -6 + 2 = -4
-6 + 2c = -4 + 2c

Add '-2c' to each side of the equation.
-6 + 2c + -2c = -4 + 2c + -2c

Combine like terms: 2c + -2c = 0
-6 + 0 = -4 + 2c + -2c
-6 = -4 + 2c + -2c

Combine like terms: 2c + -2c = 0
-6 = -4 + 0
-6 = -4

Solving
-6 = -4

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.