2(c-3)=3(c-1)

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Solution for 2(c-3)=3(c-1) equation: 



2(c-3)=3(c-1)

We move all terms to the left:

2(c-3)-(3(c-1))=0

We multiply parentheses

2c-(3(c-1))-6=0



We calculate terms in parentheses: -(3(c-1)), so:

3(c-1)

We multiply parentheses

3c-3

Back to the equation:

-(3c-3)



We get rid of parentheses

2c-3c+3-6=0

We add all the numbers together, and all the variables

-1c-3=0

We move all terms containing c to the left, all other terms to the right

-c=3

c=3/-1

c=-3

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