2(c-3)=4c-3(c+2)

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Solution for 2(c-3)=4c-3(c+2) equation: 



2(c-3)=4c-3(c+2)

We move all terms to the left:

2(c-3)-(4c-3(c+2))=0

We multiply parentheses

2c-(4c-3(c+2))-6=0



We calculate terms in parentheses: -(4c-3(c+2)), so:

4c-3(c+2)

We multiply parentheses

4c-3c-6

We add all the numbers together, and all the variables

c-6

Back to the equation:

-(c-6)



We get rid of parentheses

2c-c+6-6=0

We add all the numbers together, and all the variables

c=0

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