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2(c-3)=5(c+1)-7
We move all terms to the left:
2(c-3)-(5(c+1)-7)=0
We multiply parentheses
2c-(5(c+1)-7)-6=0
We calculate terms in parentheses: -(5(c+1)-7), so:We get rid of parentheses
5(c+1)-7
We multiply parentheses
5c+5-7
We add all the numbers together, and all the variables
5c-2
Back to the equation:
-(5c-2)
2c-5c+2-6=0
We add all the numbers together, and all the variables
-3c-4=0
We move all terms containing c to the left, all other terms to the right
-3c=4
c=4/-3
c=-1+1/3
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