2(c-4)+8=.5(6c+20)

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Solution for 2(c-4)+8=.5(6c+20) equation: 


Simplifying
2(c + -4) + 8 = 0.5(6c + 20)

Reorder the terms:
2(-4 + c) + 8 = 0.5(6c + 20)
(-4 * 2 + c * 2) + 8 = 0.5(6c + 20)
(-8 + 2c) + 8 = 0.5(6c + 20)

Reorder the terms:
-8 + 8 + 2c = 0.5(6c + 20)

Combine like terms: -8 + 8 = 0
0 + 2c = 0.5(6c + 20)
2c = 0.5(6c + 20)

Reorder the terms:
2c = 0.5(20 + 6c)
2c = (20 * 0.5 + 6c * 0.5)
2c = (10 + 3c)

Solving
2c = 10 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
2c + -3c = 10 + 3c + -3c

Combine like terms: 2c + -3c = -1c
-1c = 10 + 3c + -3c

Combine like terms: 3c + -3c = 0
-1c = 10 + 0
-1c = 10

Divide each side by '-1'.
c = -10

Simplifying
c = -10

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