2(c-4)-4=7c+3-2c

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Solution for 2(c-4)-4=7c+3-2c equation:



2(c-4)-4=7c+3-2c
We move all terms to the left:
2(c-4)-4-(7c+3-2c)=0
We add all the numbers together, and all the variables
2(c-4)-(5c+3)-4=0
We multiply parentheses
2c-(5c+3)-8-4=0
We get rid of parentheses
2c-5c-3-8-4=0
We add all the numbers together, and all the variables
-3c-15=0
We move all terms containing c to the left, all other terms to the right
-3c=15
c=15/-3
c=-5

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