2(c-4)=3(c-5)

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Solution for 2(c-4)=3(c-5) equation:


Simplifying
2(c + -4) = 3(c + -5)

Reorder the terms:
2(-4 + c) = 3(c + -5)
(-4 * 2 + c * 2) = 3(c + -5)
(-8 + 2c) = 3(c + -5)

Reorder the terms:
-8 + 2c = 3(-5 + c)
-8 + 2c = (-5 * 3 + c * 3)
-8 + 2c = (-15 + 3c)

Solving
-8 + 2c = -15 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
-8 + 2c + -3c = -15 + 3c + -3c

Combine like terms: 2c + -3c = -1c
-8 + -1c = -15 + 3c + -3c

Combine like terms: 3c + -3c = 0
-8 + -1c = -15 + 0
-8 + -1c = -15

Add '8' to each side of the equation.
-8 + 8 + -1c = -15 + 8

Combine like terms: -8 + 8 = 0
0 + -1c = -15 + 8
-1c = -15 + 8

Combine like terms: -15 + 8 = -7
-1c = -7

Divide each side by '-1'.
c = 7

Simplifying
c = 7

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