2(c-5)=3(c-8)

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Solution for 2(c-5)=3(c-8) equation: 


Simplifying
2(c + -5) = 3(c + -8)

Reorder the terms:
2(-5 + c) = 3(c + -8)
(-5 * 2 + c * 2) = 3(c + -8)
(-10 + 2c) = 3(c + -8)

Reorder the terms:
-10 + 2c = 3(-8 + c)
-10 + 2c = (-8 * 3 + c * 3)
-10 + 2c = (-24 + 3c)

Solving
-10 + 2c = -24 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
-10 + 2c + -3c = -24 + 3c + -3c

Combine like terms: 2c + -3c = -1c
-10 + -1c = -24 + 3c + -3c

Combine like terms: 3c + -3c = 0
-10 + -1c = -24 + 0
-10 + -1c = -24

Add '10' to each side of the equation.
-10 + 10 + -1c = -24 + 10

Combine like terms: -10 + 10 = 0
0 + -1c = -24 + 10
-1c = -24 + 10

Combine like terms: -24 + 10 = -14
-1c = -14

Divide each side by '-1'.
c = 14

Simplifying
c = 14

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