2(c-6)=7(c+4)

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Solution for 2(c-6)=7(c+4) equation: 



2(c-6)=7(c+4)

We move all terms to the left:

2(c-6)-(7(c+4))=0

We multiply parentheses

2c-(7(c+4))-12=0



We calculate terms in parentheses: -(7(c+4)), so:

7(c+4)

We multiply parentheses

7c+28

Back to the equation:

-(7c+28)



We get rid of parentheses

2c-7c-28-12=0

We add all the numbers together, and all the variables

-5c-40=0

We move all terms containing c to the left, all other terms to the right

-5c=40

c=40/-5

c=-8

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