2(c-7)=3(c+2)

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Solution for 2(c-7)=3(c+2) equation: 



2(c-7)=3(c+2)

We move all terms to the left:

2(c-7)-(3(c+2))=0

We multiply parentheses

2c-(3(c+2))-14=0



We calculate terms in parentheses: -(3(c+2)), so:

3(c+2)

We multiply parentheses

3c+6

Back to the equation:

-(3c+6)



We get rid of parentheses

2c-3c-6-14=0

We add all the numbers together, and all the variables

-1c-20=0

We move all terms containing c to the left, all other terms to the right

-c=20

c=20/-1

c=-20

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