2(c-7)=3(c+2)

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Solution for 2(c-7)=3(c+2) equation:



2(c-7)=3(c+2)
We move all terms to the left:
2(c-7)-(3(c+2))=0
We multiply parentheses
2c-(3(c+2))-14=0
We calculate terms in parentheses: -(3(c+2)), so:
3(c+2)
We multiply parentheses
3c+6
Back to the equation:
-(3c+6)
We get rid of parentheses
2c-3c-6-14=0
We add all the numbers together, and all the variables
-1c-20=0
We move all terms containing c to the left, all other terms to the right
-c=20
c=20/-1
c=-20

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