2(d+-8)=-10

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Solution for 2(d+-8)=-10 equation: 



2(d+-8)=-10

We move all terms to the left:

2(d+-8)-(-10)=0

We add all the numbers together, and all the variables

2(d-8)-(-10)=0

We add all the numbers together, and all the variables

2(d-8)+10=0

We multiply parentheses

2d-16+10=0

We add all the numbers together, and all the variables

2d-6=0

We move all terms containing d to the left, all other terms to the right

2d=6

d=6/2

d=3

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