2(d+1)+3(d+2)+4=5(d+3)-3

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Solution for 2(d+1)+3(d+2)+4=5(d+3)-3 equation: 



2(d+1)+3(d+2)+4=5(d+3)-3

We move all terms to the left:

2(d+1)+3(d+2)+4-(5(d+3)-3)=0

We multiply parentheses

2d+3d-(5(d+3)-3)+2+6+4=0



We calculate terms in parentheses: -(5(d+3)-3), so:

5(d+3)-3

We multiply parentheses

5d+15-3

We add all the numbers together, and all the variables

5d+12

Back to the equation:

-(5d+12)



We add all the numbers together, and all the variables

5d-(5d+12)+12=0

We get rid of parentheses

5d-5d-12+12=0

We add all the numbers together, and all the variables

=0

d=0/1

d=0

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