2(d+1)+3(d+2)=23

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Solution for 2(d+1)+3(d+2)=23 equation:


Simplifying
2(d + 1) + 3(d + 2) = 23

Reorder the terms:
2(1 + d) + 3(d + 2) = 23
(1 * 2 + d * 2) + 3(d + 2) = 23
(2 + 2d) + 3(d + 2) = 23

Reorder the terms:
2 + 2d + 3(2 + d) = 23
2 + 2d + (2 * 3 + d * 3) = 23
2 + 2d + (6 + 3d) = 23

Reorder the terms:
2 + 6 + 2d + 3d = 23

Combine like terms: 2 + 6 = 8
8 + 2d + 3d = 23

Combine like terms: 2d + 3d = 5d
8 + 5d = 23

Solving
8 + 5d = 23

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 5d = 23 + -8

Combine like terms: 8 + -8 = 0
0 + 5d = 23 + -8
5d = 23 + -8

Combine like terms: 23 + -8 = 15
5d = 15

Divide each side by '5'.
d = 3

Simplifying
d = 3

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