2(d+2)=4(d+5)

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Solution for 2(d+2)=4(d+5) equation:



2(d+2)=4(d+5)
We move all terms to the left:
2(d+2)-(4(d+5))=0
We multiply parentheses
2d-(4(d+5))+4=0
We calculate terms in parentheses: -(4(d+5)), so:
4(d+5)
We multiply parentheses
4d+20
Back to the equation:
-(4d+20)
We get rid of parentheses
2d-4d-20+4=0
We add all the numbers together, and all the variables
-2d-16=0
We move all terms containing d to the left, all other terms to the right
-2d=16
d=16/-2
d=-8

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