2(d+2)=4(d+5)

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Solution for 2(d+2)=4(d+5) equation: 



2(d+2)=4(d+5)

We move all terms to the left:

2(d+2)-(4(d+5))=0

We multiply parentheses

2d-(4(d+5))+4=0



We calculate terms in parentheses: -(4(d+5)), so:

4(d+5)

We multiply parentheses

4d+20

Back to the equation:

-(4d+20)



We get rid of parentheses

2d-4d-20+4=0

We add all the numbers together, and all the variables

-2d-16=0

We move all terms containing d to the left, all other terms to the right

-2d=16

d=16/-2

d=-8

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