2(d+2)=6+-d

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Solution for 2(d+2)=6+-d equation: 



2(d+2)=6+-d

We move all terms to the left:

2(d+2)-(6+-d)=0

We add all the numbers together, and all the variables

2(d+2)-(-1d)=0

We multiply parentheses

2d-(-1d)+4=0

We get rid of parentheses

2d+1d+4=0

We add all the numbers together, and all the variables

3d+4=0

We move all terms containing d to the left, all other terms to the right

3d=-4

d=-4/3

d=-1+1/3

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