2(d+3)+4(d-1)=14

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Solution for 2(d+3)+4(d-1)=14 equation:


Simplifying
2(d + 3) + 4(d + -1) = 14

Reorder the terms:
2(3 + d) + 4(d + -1) = 14
(3 * 2 + d * 2) + 4(d + -1) = 14
(6 + 2d) + 4(d + -1) = 14

Reorder the terms:
6 + 2d + 4(-1 + d) = 14
6 + 2d + (-1 * 4 + d * 4) = 14
6 + 2d + (-4 + 4d) = 14

Reorder the terms:
6 + -4 + 2d + 4d = 14

Combine like terms: 6 + -4 = 2
2 + 2d + 4d = 14

Combine like terms: 2d + 4d = 6d
2 + 6d = 14

Solving
2 + 6d = 14

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 6d = 14 + -2

Combine like terms: 2 + -2 = 0
0 + 6d = 14 + -2
6d = 14 + -2

Combine like terms: 14 + -2 = 12
6d = 12

Divide each side by '6'.
d = 2

Simplifying
d = 2

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