2(d+4)-5=(d+3)

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Solution for 2(d+4)-5=(d+3) equation: 



2(d+4)-5=(d+3)

We move all terms to the left:

2(d+4)-5-((d+3))=0

We multiply parentheses

2d-((d+3))+8-5=0



We calculate terms in parentheses: -((d+3)), so:

(d+3)

We get rid of parentheses

d+3

Back to the equation:

-(d+3)



We add all the numbers together, and all the variables

2d-(d+3)+3=0

We get rid of parentheses

2d-d-3+3=0

We add all the numbers together, and all the variables

d=0

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