2(d+5)+3(2d+4)=62

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Solution for 2(d+5)+3(2d+4)=62 equation: 



2(d+5)+3(2d+4)=62

We move all terms to the left:

2(d+5)+3(2d+4)-(62)=0

We multiply parentheses

2d+6d+10+12-62=0

We add all the numbers together, and all the variables

8d-40=0

We move all terms containing d to the left, all other terms to the right

8d=40

d=40/8

d=5

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