2(d+5)-7=3(d-2)

Solution for 2(d+5)-7=3(d-2) equation:

2(d+5)-7=3(d-2)

We move all terms to the left:

2(d+5)-7-(3(d-2))=0

We multiply parentheses

2d-(3(d-2))+10-7=0


We calculate terms in parentheses: -(3(d-2)), so:

3(d-2)

We multiply parentheses

3d-6

Back to the equation:

-(3d-6)


We add all the numbers together, and all the variables

2d-(3d-6)+3=0

We get rid of parentheses

2d-3d+6+3=0

We add all the numbers together, and all the variables

-1d+9=0

We move all terms containing d to the left, all other terms to the right

-d=-9

d=-9/-1

d=+9