2(d+7)-1=(8d/4)+13

Solution for 2(d+7)-1=(8d/4)+13 equation:

2(d+7)-1=(8d/4)+13

We move all terms to the left:

2(d+7)-1-((8d/4)+13)=0

We add all the numbers together, and all the variables

2(d+7)-((+8d/4)+13)-1=0

We multiply parentheses

2d-((+8d/4)+13)+14-1=0

We multiply all the terms by the denominator


2d*4)+13)-((+8d+14*4)+13)-1*4)+13)=0

We add all the numbers together, and all the variables

2d*4)+13)-((8d+56)+13)-1*4)+13)=0

We add all the numbers together, and all the variables

2d*4)+13)-((8d=0

Wy multiply elements

8d^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$d=\frac{-b}{2a}=\frac{0}{16}=0$