2(d-1)=2(4d+3)+1

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Solution for 2(d-1)=2(4d+3)+1 equation: 



2(d-1)=2(4d+3)+1

We move all terms to the left:

2(d-1)-(2(4d+3)+1)=0

We multiply parentheses

2d-(2(4d+3)+1)-2=0



We calculate terms in parentheses: -(2(4d+3)+1), so:

2(4d+3)+1

We multiply parentheses

8d+6+1

We add all the numbers together, and all the variables

8d+7

Back to the equation:

-(8d+7)



We get rid of parentheses

2d-8d-7-2=0

We add all the numbers together, and all the variables

-6d-9=0

We move all terms containing d to the left, all other terms to the right

-6d=9

d=9/-6

d=-1+1/2

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