2(d-2)=12+(.33d)

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Solution for 2(d-2)=12+(.33d) equation: 



2(d-2)=12+(.33d)

We move all terms to the left:

2(d-2)-(12+(.33d))=0

We add all the numbers together, and all the variables

2(d-2)-(12+(+.33d))=0

We multiply parentheses

2d-(12+(+.33d))-4=0



We calculate terms in parentheses: -(12+(+.33d)), so:

12+(+.33d)

determiningTheFunctionDomain
(+.33d)+12

We get rid of parentheses

.33d+12

Back to the equation:

-(.33d+12)



We get rid of parentheses

2d-.33d-12-4=0

We add all the numbers together, and all the variables

1.67d-16=0

We move all terms containing d to the left, all other terms to the right

1.67d=16

d=16/1.67

d=9+0.97/1.67

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