2(d-3)+3d=29

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Solution for 2(d-3)+3d=29 equation: 



2(d-3)+3d=29

We move all terms to the left:

2(d-3)+3d-(29)=0

We add all the numbers together, and all the variables

3d+2(d-3)-29=0

We multiply parentheses

3d+2d-6-29=0

We add all the numbers together, and all the variables

5d-35=0

We move all terms containing d to the left, all other terms to the right

5d=35

d=35/5

d=7

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