2(d-3)=4d+1

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Solution for 2(d-3)=4d+1 equation: 



2(d-3)=4d+1

We move all terms to the left:

2(d-3)-(4d+1)=0

We multiply parentheses

2d-(4d+1)-6=0

We get rid of parentheses

2d-4d-1-6=0

We add all the numbers together, and all the variables

-2d-7=0

We move all terms containing d to the left, all other terms to the right

-2d=7

d=7/-2

d=-3+1/2

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