2(d-4)=5(d-7)

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Solution for 2(d-4)=5(d-7) equation: 



2(d-4)=5(d-7)

We move all terms to the left:

2(d-4)-(5(d-7))=0

We multiply parentheses

2d-(5(d-7))-8=0



We calculate terms in parentheses: -(5(d-7)), so:

5(d-7)

We multiply parentheses

5d-35

Back to the equation:

-(5d-35)



We get rid of parentheses

2d-5d+35-8=0

We add all the numbers together, and all the variables

-3d+27=0

We move all terms containing d to the left, all other terms to the right

-3d=-27

d=-27/-3

d=+9

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