2(d-6)=4d+20

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Solution for 2(d-6)=4d+20 equation:



2(d-6)=4d+20
We move all terms to the left:
2(d-6)-(4d+20)=0
We multiply parentheses
2d-(4d+20)-12=0
We get rid of parentheses
2d-4d-20-12=0
We add all the numbers together, and all the variables
-2d-32=0
We move all terms containing d to the left, all other terms to the right
-2d=32
d=32/-2
d=-16

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