2(f+1)=3(2f-1)

Solution for 2(f+1)=3(2f-1) equation:

Simplifying
2(f + 1) = 3(2f + -1)

Reorder the terms:
2(1 + f) = 3(2f + -1)
(1 * 2 + f * 2) = 3(2f + -1)
(2 + 2f) = 3(2f + -1)

Reorder the terms:
2 + 2f = 3(-1 + 2f)
2 + 2f = (-1 * 3 + 2f * 3)
2 + 2f = (-3 + 6f)

Solving
2 + 2f = -3 + 6f

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-6f' to each side of the equation.
2 + 2f + -6f = -3 + 6f + -6f

Combine like terms: 2f + -6f = -4f
2 + -4f = -3 + 6f + -6f

Combine like terms: 6f + -6f = 0
2 + -4f = -3 + 0
2 + -4f = -3

Add '-2' to each side of the equation.
2 + -2 + -4f = -3 + -2

Combine like terms: 2 + -2 = 0
0 + -4f = -3 + -2
-4f = -3 + -2

Combine like terms: -3 + -2 = -5
-4f = -5

Divide each side by '-4'.
f = 1.25

Simplifying
f = 1.25