2(f+1)=3(f-2)

Solution for 2(f+1)=3(f-2) equation:

Simplifying
2(f + 1) = 3(f + -2)

Reorder the terms:
2(1 + f) = 3(f + -2)
(1 * 2 + f * 2) = 3(f + -2)
(2 + 2f) = 3(f + -2)

Reorder the terms:
2 + 2f = 3(-2 + f)
2 + 2f = (-2 * 3 + f * 3)
2 + 2f = (-6 + 3f)

Solving
2 + 2f = -6 + 3f

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-3f' to each side of the equation.
2 + 2f + -3f = -6 + 3f + -3f

Combine like terms: 2f + -3f = -1f
2 + -1f = -6 + 3f + -3f

Combine like terms: 3f + -3f = 0
2 + -1f = -6 + 0
2 + -1f = -6

Add '-2' to each side of the equation.
2 + -2 + -1f = -6 + -2

Combine like terms: 2 + -2 = 0
0 + -1f = -6 + -2
-1f = -6 + -2

Combine like terms: -6 + -2 = -8
-1f = -8

Divide each side by '-1'.
f = 8

Simplifying
f = 8