2(f+1)=5(f-2)

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Solution for 2(f+1)=5(f-2) equation: 


Simplifying
2(f + 1) = 5(f + -2)

Reorder the terms:
2(1 + f) = 5(f + -2)
(1 * 2 + f * 2) = 5(f + -2)
(2 + 2f) = 5(f + -2)

Reorder the terms:
2 + 2f = 5(-2 + f)
2 + 2f = (-2 * 5 + f * 5)
2 + 2f = (-10 + 5f)

Solving
2 + 2f = -10 + 5f

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-5f' to each side of the equation.
2 + 2f + -5f = -10 + 5f + -5f

Combine like terms: 2f + -5f = -3f
2 + -3f = -10 + 5f + -5f

Combine like terms: 5f + -5f = 0
2 + -3f = -10 + 0
2 + -3f = -10

Add '-2' to each side of the equation.
2 + -2 + -3f = -10 + -2

Combine like terms: 2 + -2 = 0
0 + -3f = -10 + -2
-3f = -10 + -2

Combine like terms: -10 + -2 = -12
-3f = -12

Divide each side by '-3'.
f = 4

Simplifying
f = 4

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