2(f+2)-5f+-1=20

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Solution for 2(f+2)-5f+-1=20 equation: 



2(f+2)-5f+-1=20

We move all terms to the left:

2(f+2)-5f+-1-(20)=0

determiningTheFunctionDomain
2(f+2)-5f-1-20+=0

We add all the numbers together, and all the variables

-5f+2(f+2)=0

We multiply parentheses

-5f+2f+4=0

We add all the numbers together, and all the variables

-3f+4=0

We move all terms containing f to the left, all other terms to the right

-3f=-4

f=-4/-3

f=1+1/3

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