2(f+3)+(2-5)+4f=6+6f

Solution for 2(f+3)+(2-5)+4f=6+6f equation:

Simplifying
2(f + 3) + (2 + -5) + 4f = 6 + 6f

Reorder the terms:
2(3 + f) + (2 + -5) + 4f = 6 + 6f
(3 * 2 + f * 2) + (2 + -5) + 4f = 6 + 6f
(6 + 2f) + (2 + -5) + 4f = 6 + 6f

Combine like terms: 2 + -5 = -3
6 + 2f + (-3) + 4f = 6 + 6f
6 + 2f + -3 + 4f = 6 + 6f

Reorder the terms:
6 + -3 + 2f + 4f = 6 + 6f

Combine like terms: 6 + -3 = 3
3 + 2f + 4f = 6 + 6f

Combine like terms: 2f + 4f = 6f
3 + 6f = 6 + 6f

Add '-6f' to each side of the equation.
3 + 6f + -6f = 6 + 6f + -6f

Combine like terms: 6f + -6f = 0
3 + 0 = 6 + 6f + -6f
3 = 6 + 6f + -6f

Combine like terms: 6f + -6f = 0
3 = 6 + 0
3 = 6

Solving
3 = 6

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.