2(f+3)+4f=6+68

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Solution for 2(f+3)+4f=6+68 equation:


2 (f+3)+4f=6+68

We simplify the equation to the form, which is simple to understand 
2(f+3)+4f=6+68

Reorder the terms in parentheses
+(+2f+6)+4f=6+68

Remove unnecessary parentheses
+2f+6+4f=+6+68

We move all terms containing f to the left and all other terms to the right. 
+2f+4f=+6+68-6

We simplify left and right side of the equation. 
+6f=+68

We divide both sides of the equation by 6 to get f. 
f=11.3333333333

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