2(f+3)+5=27

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Solution for 2(f+3)+5=27 equation: 



2(f+3)+5=27

We move all terms to the left:

2(f+3)+5-(27)=0

We add all the numbers together, and all the variables

2(f+3)-22=0

We multiply parentheses

2f+6-22=0

We add all the numbers together, and all the variables

2f-16=0

We move all terms containing f to the left, all other terms to the right

2f=16

f=16/2

f=8

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