2(f+3)=12(7)

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Solution for 2(f+3)=12(7) equation: 



2(f+3)=12(7)

We move all terms to the left:

2(f+3)-(12(7))=0

determiningTheFunctionDomain
2(f+3)-127=0

We multiply parentheses

2f+6-127=0

We add all the numbers together, and all the variables

2f-121=0

We move all terms containing f to the left, all other terms to the right

2f=121

f=121/2

f=60+1/2

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