2(f+3)=4(2+2f)

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Solution for 2(f+3)=4(2+2f) equation: 



2(f+3)=4(2+2f)

We move all terms to the left:

2(f+3)-(4(2+2f))=0

We add all the numbers together, and all the variables

2(f+3)-(4(2f+2))=0

We multiply parentheses

2f-(4(2f+2))+6=0



We calculate terms in parentheses: -(4(2f+2)), so:

4(2f+2)

We multiply parentheses

8f+8

Back to the equation:

-(8f+8)



We get rid of parentheses

2f-8f-8+6=0

We add all the numbers together, and all the variables

-6f-2=0

We move all terms containing f to the left, all other terms to the right

-6f=2

f=2/-6

f=-1/3

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