2(f-20)+3f=10

Solution for 2(f-20)+3f=10 equation:

Simplifying
2(f + -20) + 3f = 10

Reorder the terms:
2(-20 + f) + 3f = 10
(-20 * 2 + f * 2) + 3f = 10
(-40 + 2f) + 3f = 10

Combine like terms: 2f + 3f = 5f
-40 + 5f = 10

Solving
-40 + 5f = 10

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '40' to each side of the equation.
-40 + 40 + 5f = 10 + 40

Combine like terms: -40 + 40 = 0
0 + 5f = 10 + 40
5f = 10 + 40

Combine like terms: 10 + 40 = 50
5f = 50

Divide each side by '5'.
f = 10

Simplifying
f = 10