2(g+4)=4(1/2g+2)

Solution for 2(g+4)=4(1/2g+2) equation:

2(g+4)=4(1/2g+2)

We move all terms to the left:

2(g+4)-(4(1/2g+2))=0


Domain of the equation: 2g+2))!=0

g∈R


We multiply parentheses

2g-(4(1/2g+2))+8=0

We multiply all the terms by the denominator


2g*2g+8*2g+2))-(4(1+2))=0

We add all the numbers together, and all the variables

2g*2g+8*2g+2))-(43)=0

We add all the numbers together, and all the variables

2g*2g+8*2g=0

Wy multiply elements

4g^2+16g=0

a = 4; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·4·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*4}=\frac{-32}{8}
=-4
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*4}=\frac{0}{8}
=0
$