2(g+6)+10=3(g-1)+20

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Solution for 2(g+6)+10=3(g-1)+20 equation: 



2(g+6)+10=3(g-1)+20

We move all terms to the left:

2(g+6)+10-(3(g-1)+20)=0

We multiply parentheses

2g-(3(g-1)+20)+12+10=0



We calculate terms in parentheses: -(3(g-1)+20), so:

3(g-1)+20

We multiply parentheses

3g-3+20

We add all the numbers together, and all the variables

3g+17

Back to the equation:

-(3g+17)



We add all the numbers together, and all the variables

2g-(3g+17)+22=0

We get rid of parentheses

2g-3g-17+22=0

We add all the numbers together, and all the variables

-1g+5=0

We move all terms containing g to the left, all other terms to the right

-g=-5

g=-5/-1

g=+5

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