2(h+2)-3h=5-3(h+1)

Solution for 2(h+2)-3h=5-3(h+1) equation:

2(h+2)-3h=5-3(h+1)

We move all terms to the left:

2(h+2)-3h-(5-3(h+1))=0

We add all the numbers together, and all the variables

-3h+2(h+2)-(5-3(h+1))=0

We multiply parentheses

-3h+2h-(5-3(h+1))+4=0


We calculate terms in parentheses: -(5-3(h+1)), so:

5-3(h+1)

determiningTheFunctionDomain
-3(h+1)+5

We multiply parentheses

-3h-3+5

We add all the numbers together, and all the variables

-3h+2

Back to the equation:

-(-3h+2)


We add all the numbers together, and all the variables

-1h-(-3h+2)+4=0

We get rid of parentheses

-1h+3h-2+4=0

We add all the numbers together, and all the variables

2h+2=0

We move all terms containing h to the left, all other terms to the right

2h=-2

h=-2/2

h=-1