2(h+3)-(h-2)=2(h+3)

Solution for 2(h+3)-(h-2)=2(h+3) equation:

2(h+3)-(h-2)=2(h+3)

We move all terms to the left:

2(h+3)-(h-2)-(2(h+3))=0

We multiply parentheses

2h-(h-2)-(2(h+3))+6=0

We get rid of parentheses

2h-h-(2(h+3))+2+6=0


We calculate terms in parentheses: -(2(h+3)), so:

2(h+3)

We multiply parentheses

2h+6

Back to the equation:

-(2h+6)


We add all the numbers together, and all the variables

h-(2h+6)+8=0

We get rid of parentheses

h-2h-6+8=0

We add all the numbers together, and all the variables

-1h+2=0

We move all terms containing h to the left, all other terms to the right

-h=-2

h=-2/-1

h=+2