2(h+3)=1/6(12h+21)

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Solution for 2(h+3)=1/6(12h+21) equation: 


h in (-oo:+oo)

2*(h+3) = (1/6)*(12*h+21) // - (1/6)*(12*h+21)

2*(h+3)-((1/6)*(12*h+21)) = 0

2*(h+3)+(-1/6)*(12*h+21) = 0

2*(h+3)-1/6*(12*h+21) = 0

2*(h+3)-1/6*(12*h+21) = 0

5/2 = 0

5/2 = 0

5/2 = 0 // * 2

5 = 0

h belongs to the empty set

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