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h in (-oo:+oo)
2*(h+3) = (1/6)*(12*h+36) // - (1/6)*(12*h+36)
2*(h+3)-((1/6)*(12*h+36)) = 0
2*(h+3)+(-1/6)*(12*h+36) = 0
2*(h+3)-1/6*(12*h+36) = 0
2*(h+3)-1/6*(12*h+36) = 0
0 = 0
0 = 0
h belongs to the empty set
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