2(h+4)+h=53

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Solution for 2(h+4)+h=53 equation:



2(h+4)+h=53
We move all terms to the left:
2(h+4)+h-(53)=0
We add all the numbers together, and all the variables
h+2(h+4)-53=0
We multiply parentheses
h+2h+8-53=0
We add all the numbers together, and all the variables
3h-45=0
We move all terms containing h to the left, all other terms to the right
3h=45
h=45/3
h=15

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