2(h+4)+h=53

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Solution for 2(h+4)+h=53 equation: 



2(h+4)+h=53

We move all terms to the left:

2(h+4)+h-(53)=0

We add all the numbers together, and all the variables

h+2(h+4)-53=0

We multiply parentheses

h+2h+8-53=0

We add all the numbers together, and all the variables

3h-45=0

We move all terms containing h to the left, all other terms to the right

3h=45

h=45/3

h=15

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