2(h+5)-3(h-2)=5(2h-1)

Solution for 2(h+5)-3(h-2)=5(2h-1) equation:

2(h+5)-3(h-2)=5(2h-1)

We move all terms to the left:

2(h+5)-3(h-2)-(5(2h-1))=0

We multiply parentheses

2h-3h-(5(2h-1))+10+6=0


We calculate terms in parentheses: -(5(2h-1)), so:

5(2h-1)

We multiply parentheses

10h-5

Back to the equation:

-(10h-5)


We add all the numbers together, and all the variables

-1h-(10h-5)+16=0

We get rid of parentheses

-1h-10h+5+16=0

We add all the numbers together, and all the variables

-11h+21=0

We move all terms containing h to the left, all other terms to the right

-11h=-21

h=-21/-11

h=1+10/11