2(h-3)+5h=5(2+h)

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Solution for 2(h-3)+5h=5(2+h) equation: 



2(h-3)+5h=5(2+h)

We move all terms to the left:

2(h-3)+5h-(5(2+h))=0

We add all the numbers together, and all the variables

2(h-3)+5h-(5(h+2))=0

We add all the numbers together, and all the variables

5h+2(h-3)-(5(h+2))=0

We multiply parentheses

5h+2h-(5(h+2))-6=0



We calculate terms in parentheses: -(5(h+2)), so:

5(h+2)

We multiply parentheses

5h+10

Back to the equation:

-(5h+10)



We add all the numbers together, and all the variables

7h-(5h+10)-6=0

We get rid of parentheses

7h-5h-10-6=0

We add all the numbers together, and all the variables

2h-16=0

We move all terms containing h to the left, all other terms to the right

2h=16

h=16/2

h=8

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