2(h-3)=5(h-2)

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Solution for 2(h-3)=5(h-2) equation: 



2(h-3)=5(h-2)

We move all terms to the left:

2(h-3)-(5(h-2))=0

We multiply parentheses

2h-(5(h-2))-6=0



We calculate terms in parentheses: -(5(h-2)), so:

5(h-2)

We multiply parentheses

5h-10

Back to the equation:

-(5h-10)



We get rid of parentheses

2h-5h+10-6=0

We add all the numbers together, and all the variables

-3h+4=0

We move all terms containing h to the left, all other terms to the right

-3h=-4

h=-4/-3

h=1+1/3

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