2(h-5)+6=7(h-1)-2(h-6)

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Solution for 2(h-5)+6=7(h-1)-2(h-6) equation: 



2(h-5)+6=7(h-1)-2(h-6)

We move all terms to the left:

2(h-5)+6-(7(h-1)-2(h-6))=0

We multiply parentheses

2h-(7(h-1)-2(h-6))-10+6=0



We calculate terms in parentheses: -(7(h-1)-2(h-6)), so:

7(h-1)-2(h-6)

We multiply parentheses

7h-2h-7+12

We add all the numbers together, and all the variables

5h+5

Back to the equation:

-(5h+5)



We add all the numbers together, and all the variables

2h-(5h+5)-4=0

We get rid of parentheses

2h-5h-5-4=0

We add all the numbers together, and all the variables

-3h-9=0

We move all terms containing h to the left, all other terms to the right

-3h=9

h=9/-3

h=-3

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